ls3-www.cs.tu-dortmund.de/cms/medien/publikationen/techreport810.pdf
(offerP(n+1) = bidC(n+1)), or there will be no match for the curves during CYCk, according to the lemma above.
Proof of theorem 3.1.2: Since
I. We have
( 1) ( 1)0 0 2 21 1
( 1) ( 1)0 0 0 01 1
( 1) ( 1)0 0 1 [...] into [½(Bk+1 + Ak+1), Bk+1] or [Ak+1, ½(Bk+1 + Ak+1)], respectively.
If the check is positive the values remain un- changed for level (k+1). Otherwise the value would be outside of [Ak+1, Bk+1], and the [...] 1 1
(1),(2)
(3),(4)
log( ) log( )
0 0
0 ( 1) ( 1) 1 1
1 1
urg n urg n C Ps tC P
urg n urg n k ks tC P
urg n urg n s tC P
C P
k ks t
k kB bid offer A
k k k
bid n offer n
B A ee
B A ee
B bid offer A B A …